How to determine the limits for triple integration?

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Homework Help Overview

The discussion revolves around evaluating a triple integral over a defined region in three-dimensional space, specifically focusing on the limits of integration for the variables x, y, and z. The region A is described by the conditions x, y, z > 0 and x + y + z ≤ 1, indicating a bounded area in the first octant of the coordinate system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about determining the limits for x, y, and z based on the given region A. There are discussions about the geometric interpretation of the plane defined by x + y + z = 1 and its projection onto the xy-plane. Some participants question how to visualize the projection and the implications for setting limits of integration.

Discussion Status

Participants are actively exploring the relationships between the variables and the geometric constraints of the region. Some guidance has been offered regarding the limits for z, with a suggestion to consider the equation of the plane. However, there remains confusion about the limits for x and y, indicating that the discussion is ongoing and productive.

Contextual Notes

There is a note about the importance of visualizing the region of integration, as well as a reminder about posting in the appropriate forum. Participants are encouraged to sketch the region to aid in understanding the limits.

Alex_Neof
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Homework Statement



Evaluate the triple integral:
∫ x dxdydz
A

where

A = {(x; y; z) : x, y, z > 0, x + y + z ≤ 1} .

Homework Equations



None that I know of.

The Attempt at a Solution



The problem I have is determining the limits for x, y and z. I don't really understand the following notation:

A = {(x; y; z) : x, y, z > 0, x + y + z ≤ 1} , which I believe will help me.

I'm guessing x + y + z ≤ 1 is the definition of a plane and the region A that we are integration over is in the first octant since x, y, z > 0.

Kind regards.
 
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Alex_Neof said:

Homework Statement



Evaluate the triple integral:
∫ x dxdydz
A

where

A = {(x; y; z) : x, y, z > 0, x + y + z ≤ 1} .

Homework Equations



None that I know of.

The Attempt at a Solution



The problem I have is determining the limits for x, y and z. I don't really understand the following notation:

A = {(x; y; z) : x, y, z > 0, x + y + z ≤ 1} , which I believe will help me.

I'm guessing x + y + z ≤ 1 is the definition of a plane and the region A that we are integration over is in the first octant since x, y, z > 0.

Kind regards.
You are correct.

However, in future, please post your homework in the proper HW forum. I'm moving this thread to the Calculus HW forum.
 
x+ y+ z= 1, which is the same as z= 1- x- y, is a plane crossing the three coordinate axes at (1, 0, 0), (0, 1, 0), and (0, 0, 1).

Projecting down to the xy-plane, where z= 0, we have the region bounded by the x and y axes and the line x+ y= 0. The line x+ y= 0, which is the same as y= 1- x, crosses the x and y axes at (1, 0) and (0, 1). So x goes from a smallest value of 0 to a largest value of 1. Now, if you were to draw a line parallel to the y-axis, for each x, what would the lowest and largest values of y be? If you were to draw a line parallel to the z- axis, for each (x,y), what would the smallest and largest values of y be?
 
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Ah sorry about that SteamKing. So if I consider layers along the z axis, my constant limits for z would be from 0 to 1. I still don't know how to determine the limits for x and y. I cannot visualise the projection of A onto the x-y plane.
 
Hi HallsofIvy, so for each value of x, the lowest and highest value of y would be from 0 to the line x+y=1, so the highest value will be y=x-1? Will the highest values for z be 0 to 1?

Kind regards.

ah sorry, I think my limits for z are wrong as you told me to think about z for each (x,y)
 
In cases like this, making a simple sketch can often provide clarity to what the limits are.
 
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Alex_Neof said:
Hi HallsofIvy, so for each value of x, the lowest and highest value of y would be from 0 to the line x+y=1, so the highest value will be y=x-1?
No! If x+ y= 1 then y= 1- x.

Will the highest values for z be 0 to 1?
No.

Kind regards.

ah sorry, I think my limits for z are wrong as you told me to think about z for each (x,y)
z goes from 0 to 1- x- y.
 
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HallsofIvy, why does z go from 0 to 1-x-y?
 
ah it's the equation of the plane from the xy plane to z=1- x -y for each x and y! nevermind!
Thank you! I really appreciate the help from everyone.
 

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