How to differentiate 6^(sin(pix))

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Homework Help Overview

The problem involves finding the derivative of the function y = 6^{sin(πx)}, which falls under the subject area of calculus, specifically focusing on differentiation techniques and the application of the chain rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the differentiation of exponential functions, particularly those with variable exponents. There is an exploration of the relationship between the function and its logarithmic form, with some questioning the application of the chain rule in this context. Others express confusion about the introduction of the natural logarithm in the differentiation process.

Discussion Status

Some participants have provided insights into the differentiation process, including the transformation of the function into its exponential form. There is recognition of the chain rule's role in the differentiation of such functions, and clarification is sought regarding the appearance of the natural logarithm in the derivative. The discussion appears to be productive, with participants engaging in a deeper understanding of the concepts involved.

Contextual Notes

There is mention of the original poster's surprise at being asked to differentiate this function given their current learning stage, indicating a potential gap in foundational knowledge regarding exponential differentiation rules.

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Homework Statement



Find the derivative to:

y = 6^{sin(\pi x)}

Homework Equations



You tell me

The Attempt at a Solution



I am quite surprised that we are asked to do this when we are just learning the chain rule. We have not learned how to differentiate something like a^x yet and somehow I am suppose to do this with the chain rule... If you could either let me know what the general rule is here or point me to some place that will tell me what it would be. I am not even sure what you would call such a rule, the base rule perhaps? ha

thanks!
 
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6^(sin(pi*x))=e^(log(6)*sin(pi*x)), right? That's really not that much harder than differentiating a^x=e^(log(a)*x). And it does use the chain rule.
 
Ah I was unaware that

6^{sin(\pi x)} = e^{log(6)sin(\pi x)}

I found an example problem though in the book after posting this and I found the derivative to be:

y' = \pi 6^{sin(\pi x)}(ln(6))(cos(\pi x))

which does not appear to be what you suggested doing, as the derivative does not contain an e term at all.

I just follow the book step by step so I am unaware of how the natural log of 6 actually comes in here. Could you possibly clarify what exactly went on here with my solution?

thanks Dick!
 
Actually, it's better to do a^x first. f(x)=a^x=e^(log(a)*x). f'(x)=e^(log(a)*x)*(log(a)*x)' (chain rule, right?) which is e^(log(a)*x)*log(a). Which is (a^x)*log(a), right? Notice that the 'e' doesn't appear in the initial problem nor is it in the answer. But it appears in the middle. Same with your problem.
 
Asphyxiated said:
Ah I was unaware that

6^{sin(\pi x)} = e^{log(6)sin(\pi x)}

I found an example problem though in the book after posting this and I found the derivative to be:

y' = \pi 6^{sin(\pi x)}(ln(6))(cos(\pi x))

which does not appear to be what you suggested doing, as the derivative does not contain an e term at all.

I just follow the book step by step so I am unaware of how the natural log of 6 actually comes in here. Could you possibly clarify what exactly went on here with my solution?

thanks Dick!

And the log(6) comes in because 6=e^(log(6)). So 6^x=e^(log(6)*x).
 
Thanks! Very clear, I got it now.
 

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