How to Evaluate Integrals Using Areas: A Scientific Approach

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Homework Help Overview

The discussion revolves around evaluating the integral ∫(-1,x)|t|dt using geometric areas under the curve of the function f(x) = |x|. Participants are exploring how to apply the concept of area to this integral and its relationship to the derivative of the integral.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of the function f(t) as |t| and question how to evaluate the integral using areas. Some suggest drawing the graph of f(x) to identify geometric shapes that represent the area under the curve.

Discussion Status

The conversation includes attempts to clarify the use of areas in evaluating the integral, with some participants providing guidance on visualizing the function. There is acknowledgment of the correct interpretation of f(t) and its implications for the integral and its derivative.

Contextual Notes

Some participants express uncertainty about the phrase "use areas," indicating a need for clarification on how to apply this concept in the context of the integral evaluation.

dillon131222
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The Question

Let f(x) = |x|. use areas to evaluate ∫(-1,x)f(t)dt for all x. use this to show that d/dx∫(0,x)f(t)dt = f(x)

not sure hot to evaluate the integral using area when i don't know what f(t) is...
 
Last edited:
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dillon131222 said:
The Question

Let f(x) = |x|. use areas to evaluate ∫(-1,x)f(t)dt for all x. use this to show that d/dx∫f(t)dt = f(x)

not sure hot to evaluate the integral using area when i don't know what f(t) is...

f(x)=|x|. So f(t)=|t|.
 
dillon131222 said:
The Question

Let f(x) = |x|. use areas to evaluate ∫(-1,x)f(t)dt for all x. use this to show that d/dx∫f(t)dt = f(x)

not sure hot to evaluate the integral using area when i don't know what f(t) is...

You know what f is.

You know what mathematical symbolism is. :wink:
 
As to your next question, I'm not sure what you mean by "use areas", but I recommend that you draw out what f(x) looks like. Then, see if you can spot an elementary shape the area under -1 to 0 looks like and the same with the area under 0 to x.
 
Dick said:
f(x)=|x|. So f(t)=|t|.

oh.. you that's kinda obvious now that you point it out :P thanks :)

Karnage1993 said:
As to your next question, I'm not sure what you mean by "use areas", but I recommend that you draw out what f(x) looks like. Then, see if you can spot an elementary shape the area under -1 to 0 looks like and the same with the area under 0 to x.

ya that's basically what using the area is :P just didnt clue into what f(t) was :P
 
so here's my attempt:

http://img692.imageshack.us/img692/3284/graphed.png
with f(x) = |x| so f(t) = |t| graphed above, and the area from -1 to x would be

(1/2)t2 -1/2 = ∫(-1,x)f(t)dt, so

d/dx(∫(0,x)f(t)dt) = f(x)

d/dx(1/2x2) = |x|

x = |x|

that seem correct?
 
Last edited by a moderator:
Yes, it's correct, but I have to be picky in how you showed it. You should start with the LHS of what you want to show, ie, d/dx∫(0,x)f(t)dt, and simplify it to f(x). Like this:

LHS
= d/dx∫(0,x)f(t)dt
= d/dx((1/2)x^2)
= x
= |x|...[since x >= 0]
= f(x), which is what we wanted to show. □
 
Last edited:

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