How to express ##3^{\sqrt(2)}## in terms of natural logarithms

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SUMMARY

The discussion focuses on expressing the mathematical expression ##3^{\sqrt{2}}## in terms of natural logarithms. Participants confirm that the expression can be represented as ##e^{\sqrt{2} \ln{3}}##, but debate whether this is the desired form. The transformation of the expression using logarithmic properties is emphasized, particularly the relationship ##\ln(3^{\sqrt{2}}) = \sqrt{2} \ln(3)##. The conversation highlights the need for clarity in the problem statement, as participants question the sufficiency of the provided information.

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  • Understanding of exponential functions
  • Familiarity with natural logarithms
  • Knowledge of logarithmic identities
  • Basic calculus concepts
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  • Learn how to manipulate expressions involving natural logarithms
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Students studying calculus, particularly those focusing on transcendental functions, as well as educators seeking to clarify logarithmic transformations in mathematical expressions.

MevsEinstein
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What the title says
So in my Calculus book, it asked a question in its Transcendental Functions chapter. It wanted me to express ##3^{\sqrt{2}}## in terms of natural logarithms I have no idea how to solve this. All I know is that ##3^{\sqrt{2}} = e^{\sqrt{2}\ln{3}}## but that's not completely in natural logarithm form.
 
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MevsEinstein said:
All I know is that ##3^{sqrt{2}} = e^{2*ln{3}}##
Are you sure?
MevsEinstein said:
but that's not completely in natural logarithm form.
Perhaps that form is what they want?
 
MevsEinstein said:
Summary:: What the title says

So in my Calculus book, it asked a question in its Transcendental Functions chapter. It wanted me to express ##3^{\sqrt{2}}## in terms of natural logarithms I have no idea how to solve this. All I know is that ##3^{\sqrt{2}} = e^{2\ln{3}}## but that's not completely in natural logarithm form.
You should correct your mistake, then write ##x=3^{\sqrt{2}}## and transform it via logarithm and exponentiation.
 
Maybe ##ln(3^{\sqrt{2}})=\sqrt{2}ln(3)?##
 
mathman said:
Maybe ##ln(3^{\sqrt{2}})=\sqrt{2}ln(3)?##
The question was to represent ##3^\sqrt{2}## as natural logarithms. ##\sqrt{2} \ln{3}## won't be the answer
 
MevsEinstein said:
The question was to represent ##3^\sqrt{2}## as natural logarithms. ##\sqrt{2} \ln{3}## won't be the answer
Again. Set ##x=3^{\sqrt{2}}## and rewrite it as ##x=e^{\ln x}## with appropriate changes on the right.
 
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## \ln \exp \left (3^{\sqrt{2}}\right) ## seems to do the trick
 
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I think this question is underspecified. Do you have some other examples with correct solutions so we can try to figure out what they're actually looking for?
 
Office_Shredder said:
I think this question is underspecified. Do you have some other examples with correct solutions so we can try to figure out what they're actually looking for?
The book didn't have any other examples.
 
  • #10
: maybe you're supposed to do the same thing to the ##\sqrt{2}## that you did to the 3?
 
  • #11
Or simply: ##\log_3 x= \log_3 \left(3^{\sqrt{2}}\right)=\sqrt{2}##.
 

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