How to find C and L in maximum current?

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In an RLC circuit, to achieve maximum current at 90 MHz, the inductive reactance (Xl) must equal the capacitive reactance (Xc). The resistance (R) is given as 1000 ohms, and the resonance condition requires Xc + Xl = 0. To find the values of inductance (L) and capacitance (C), the Q factor must be calculated for a 10% current drop at 90.3 MHz, which helps determine the necessary reactance. Practical implementation may vary due to parasitic effects, necessitating adjustments during circuit assembly. Understanding these principles is crucial for optimizing circuit performance.
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In a RLC circuit, radio waves with different frequency, f, hit the antenna and exert oscillating electric forces on the electrons on the antenna . Thus they act via antenna as individual batteries, each oscillating at their particular frequency f. Suppose R=1000 ohm. What should L and C be so we get the largest current in the circuits at frequency in 90 MHz.However, at frequency 90.3 current is only 1/10 as large.

Now I know that at Imax, Xl=Xc, but I don't know how to use the other given frequency to find C and L.

Any help please?
 
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Welcome to PF.

I assume the R is in parallel with the L and C.
Xl = 2*Pi*f*L, Xc = -1/ (2*Pi*f*C), when Xc + Xl = 0 you have resonance.

The width of the resonance peak is determined by the Q which is the ratio of reactance to resistance. See https://en.wikipedia.org/wiki/Q_factor

So find the Q required for 10% at 90.3MHz. Then calculate the reactance needed.
Then solve for the L and C at 90MHz that have that reactance.
 
Then, if you want to build a suitable resonating circuit, you find that, at 90MHz, nothing behaves quite as you'd expect, because of parasitic effects. There can be a lot of 'suck it and see', when you bolt it into a circuit.
 
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