How to find centre of gravity for a hemisphere shell?

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SUMMARY

The discussion focuses on calculating the center of gravity (CG) for a hemisphere shell, emphasizing the integration of mass density over the surface. The key formulas for the CG in rectangular coordinates are provided: ycm = ∫ρ(x) f(x)dx and xcm = ∫ρ(x) xf(x)dx. A critical point raised is the discrepancy between the CG results obtained from integration and symmetry arguments, particularly comparing the semicircular wire's CG at (0, 2R/π) versus the hemisphere's CG at (0, 0, R/2).

PREREQUISITES
  • Understanding of mass density integration
  • Familiarity with center of mass (COM) concepts
  • Knowledge of symmetry in physical problems
  • Basic proficiency in calculus, particularly integration techniques
NEXT STEPS
  • Study the integration of mass density for various geometric shapes
  • Learn about the center of mass calculations for three-dimensional objects
  • Explore the implications of symmetry in physics problems
  • Review examples of center of mass calculations in textbooks or online resources
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Students preparing for examinations in physics or engineering, educators teaching mechanics, and anyone interested in understanding the principles of center of gravity in geometric shapes.

mick_1
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How to find centre of gravity for a hemisphere shell??

Can someone show me how to calculate centre of gravity for a hemisphere shell??
 
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These sound suspiciously like homework problems.
 
It's not homework, I'm preparing for an examination. And I have serious problem solving this assignment. Pleas help me!
 
Integrate mass density over the surface for each axial direction. As far as I can remember for rectangular coordinates its

y_{cm} = \int{\rho(x) f(x)dx}

x_{cm} = \int{\rho(x) xf(x)dx}

but my memory is probably mistaking me. There should be an example of this in your book though.
 
Here's the hint:use the rotation around Oz symmetry to transform your problem into a very simple one:finding the C of M for a semicircle of radius R.You basically need the "z" coordinate of the C of M for the hemisphere,or the "y" coordinate for the C of M for the semicircle.

Daniel.
 


The result obtained from integration and your symmetry argument are NOT the same.
For a semicircular wire, the COM is (0, \frac{2R}{\pi}) while from integration, it is (0,0,R/2). Can anybody explain this?
 


I know this is an old post, but I have been struggling with the same problem for a while now , can anyone explain this?
 

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