How to find Coefficient of Friction w/ Fa and mass?

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To find the coefficient of kinetic friction for a sled being pulled by poodles, the net force is calculated to be zero since the sled moves at a constant velocity. The applied force is 66N, and the normal force is determined using Fn = mg, resulting in 137.2N. The frictional force is then calculated using the equation Ff = u * Fn, leading to the coefficient of friction u being approximately 0.48. The calculations are confirmed to be correct, indicating a solid understanding of the problem. This method effectively demonstrates how to apply physics equations to find the coefficient of friction.
HomiesontheRise
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Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
 
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HomiesontheRise said:

Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
HomiesontheRise said:

Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.
 
So I started by finding the Net Force which was 0 due to the fact that there is no acceleration (velocity is constant).
Then found Force of Friction using Fnet and Fa with the formula Fnet=Fa+(-Ff).
Then found Fn using Fn=mg.
Finally, I user Ff=Fn*u to find u

MY WORK
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
 
Please tell me if you see any errors in my calculations
 
PhanthomJay said:
Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.
Does this look right?
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
 
Look
HomiesontheRise said:
Does this look right?
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
Looks good!
 

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