How to find exact value of x/2=sinx?

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According to Wolfram it is approx. -1.895

How do I find the exact value of the root though?
 
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What makes you think it is a root? It probably is transcendental.

Of course, 0 is an exact solution, and +1.895 is also approximately a solution.
 
Khashishi said:
What makes you think it is a root? It probably is transcendental.

Of course, 0 is an exact solution, and +1.895 is also approximately a solution.

so how do we find the exact value of 1.895?
 
greswd said:
According to Wolfram it is approx. -1.895

How do I find the exact value of the root though?
I don't believe there is a way to find the exact value of the root that is near either -1.895 or +1.895. You can approximate either of these roots to whatever precision is needed using any number of numerical techniques, such as Newton's Method, Newton-Raphson, bisection, and others.
 
Thanks. So is it transcendental?
 
I think it is transcendental as a consequence of the Lindemann–Weierstrass theorem.

If ##sin(x)## is algebraic (##x\neq 0##), so are ##x## (being equal to ##2sin(x)##) and ##cos(x)##.
That implies that ##e^{ix}## is algebraic too. But this contradict the Lindemann–Weierstrass theorem.
 
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Samy_A said:
I think it is transcendental as a consequence of the Lindemann–Weierstrass theorem.
Wiki says the following:

Numbers proven to be transcendental:
...
sin(a), cos(a) and tan(a), and their multiplicative inverses csc(a), sec(a) and cot(a), for any nonzero algebraic number a (by the Lindemann–Weierstrass theorem).
...
 
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