How to find jordan form given rank?

  • Context: Graduate 
  • Thread starter Thread starter chuy52506
  • Start date Start date
  • Tags Tags
    Form rank
Click For Summary
SUMMARY

The discussion focuses on determining the Jordan form of an 8x8 matrix A with specific ranks: rank(A)=5, rank(A^2)=2, rank(A^3)=1, and rank(A^4)=0. It is established that the largest Jordan block is 4x4, with only one such block present due to the rank of A^3 being 1. The conversation emphasizes the relationship between the ranks of the matrix powers and the configuration of the Jordan blocks, particularly how the smaller blocks contribute to the overall rank.

PREREQUISITES
  • Understanding of Jordan canonical form
  • Familiarity with matrix rank and its implications
  • Knowledge of linear algebra concepts, particularly eigenvalues and eigenvectors
  • Experience with matrix operations and transformations
NEXT STEPS
  • Study the properties of Jordan blocks in detail
  • Learn how to compute the rank of matrix powers
  • Explore examples of Jordan forms for different matrix ranks
  • Investigate the relationship between eigenvalues and the structure of Jordan blocks
USEFUL FOR

Mathematicians, linear algebra students, and anyone involved in advanced matrix theory or seeking to understand Jordan forms in the context of matrix rank analysis.

chuy52506
Messages
77
Reaction score
0
How to find jordan form given rank??

Find the jordan for of A given that A is an 8x8 matrix, rank(A)=5, rank(A^2)=2, rank(A^3)=1 and rank(A^4)=0.

I know that the largest jordan block will be 4x4 and there will be only one of them since the rank(A^3)=1 but how do i find the rest??
 
Physics news on Phys.org


well how do other blocks affect the total rank?
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K