How to Find the Base in an Equations with Unknown Numbers

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To find the base A in the equation 24)A + 17)A = 40)A, convert each number from base A to decimal form. For example, 24)A translates to 2A + 4, 17)A to 1A + 7, and 40)A to 4A. Substitute these expressions into the equation to form 2A + 4 + 1A + 7 = 4A. Simplifying this leads to a solvable equation for A. This method effectively avoids trial and error by using algebraic substitution.
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How would you solve a problem like this where you have to find what base A is for this equation to be true? So in what base are these numbers.24)A + 17)A = 40)A

Not asking the answer for this particular question but how you'd solve it (other than trial and error obviously)
 
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A two digit number ab)A in base A equals A\cdot a + b so:
24)A = 2A + 4
17)A = 1A + 7
40)A = 4A + 0
Then substitute in the equation and solve for A.
 
Simple:

24_A = 2*A^1+4*A^0 = 2A + 4

Similarly, 17_A = 1A + 7 and 40_A = 4A + 0

Substitute and solve for A
 
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