How to find the density of collector saturation current?

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Discussion Overview

The discussion revolves around finding the density of collector saturation current in a semiconductor context, specifically focusing on the parameters and equations involved in the calculation. The scope includes homework-related problem solving and technical reasoning regarding semiconductor physics.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant states they have values for various parameters such as doping concentrations, diffusion coefficients, and diffusion lengths but are uncertain about the cross-sectional area needed for the calculation.
  • Another participant points out that the question has been restated with specific values and emphasizes that without knowing the area, the computation cannot be completed.
  • A suggestion is made to assume a cross-sectional area of 1 square meter for the sake of proceeding with the calculation.

Areas of Agreement / Disagreement

Participants appear to agree on the necessity of knowing the cross-sectional area to complete the calculation, but there is no consensus on how to proceed without it.

Contextual Notes

The discussion does not resolve the issue of the unknown cross-sectional area, which is critical for the calculation of collector saturation current density.

CKaiL
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Homework Statement


Given the following formula for saturation current
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Homework Equations

The Attempt at a Solution


I am able to find the value for Dn , q , WB , ni and N AB except for the A(cross sectional area)
 
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So what is your question?
 
Find the collector saturation current density since I have the following
Doping in the emitter, NDE = 1018 cm-3,
Doping in the base, NAB = 2×1016 cm-3,
Diffusion coefficient of holes in the emitter, Dp = 1 cm2/s,
Diffusion coefficient of electrons in the base, Dn = 10 cm2/s,
Diffusion length of holes in the emitter, Lp = 0.300 μm,
Diffusion length of electrons in the base, Ln = 20 μm,
Width of the neutral region in the base, wB = 1 μm.
 
You have simply restated exactly the same problem but with specific values. You don't know the area so you can't finish the computation, right? Would you like for us to make up a cross section for you? Ok, use 1 square meter.
 

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