How to find the specific heat capacity of a mixture?

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SUMMARY

The discussion focuses on determining the specific heat capacity of water-solute mixtures, specifically using baking soda and water as an example. The user has a mixture mass of 914.75g and a temperature change of 175.8°F over 9.5 minutes but lacks the necessary variables Q (heat added) and C (specific heat capacity) for calculations. Participants suggest using an electric stove with a power output of 2500 watts to improve measurement accuracy, emphasizing the importance of controlled conditions to minimize heat loss and ensure precise results.

PREREQUISITES
  • Understanding of specific heat capacity and its significance in thermodynamics.
  • Familiarity with the equation Q = mcΔT for heat transfer calculations.
  • Knowledge of measuring temperature changes accurately.
  • Basic principles of heat transfer and experimental controls.
NEXT STEPS
  • Learn how to accurately measure heat transfer using calorimetry techniques.
  • Research the impact of heat loss in experimental setups and methods to minimize it.
  • Explore the use of electric stoves and their wattage in heat capacity experiments.
  • Investigate the calibration of experimental setups for precise thermal measurements.
USEFUL FOR

Students conducting physics experiments, educators teaching thermodynamics, and researchers interested in calorimetry and heat transfer methodologies.

timsmith98
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Homework Statement


For my physics IA, I am finding the specific heat capacity of water-solute mixtures and finding how the specific heat differs from that of just water alone. I have the mass of the mixture, for example baking soda and water was 914.75g and changed 175.8 degrees Fahrenheit in 9.5 minutes. I just need to know the specific heat capacity along with Q in the equation.

Homework Equations


upload_2015-12-14_9-29-2.png

The Attempt at a Solution


I can't find the solution because I am missing two variables: Q and C. If there's any way to find either solution, please let me know. Thank you!
 
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Do you know the imposed heating rate?
 
Chestermiller said:
Do you know the imposed heating rate?
I'm not 100% sure what you mean by this. Can you give me an example please? Thanks for the help!
 
timsmith98 said:
I'm not 100% sure what you mean by this. Can you give me an example please? Thanks for the help!
Your'e using a heater, right? What is the power input of the heater?
 
Chestermiller said:
Your'e using a heater, right? What is the power input of the heater?
I was using a gas stovetop set on high to heat it from solid form until it boiled.
 
timsmith98 said:
I was using a gas stovetop set on high to heat it from solid form until it boiled.
Too bad. Game over. You need to know the rate at which you are adding heat. You might be able to do this by first measuring how fast the water heats up when the stove is at full blast with pure water in the pot, and then use this to scale the heat capacity in your solutions. But, some of the heat also goes into the pot.

Chet
 
Chestermiller said:
Too bad. Game over. You need to know the rate at which you are adding heat. You might be able to do this by first measuring how fast the water heats up when the stove is at full blast with pure water in the pot, and then use this to scale the heat capacity in your solutions. But, some of the heat also goes into the pot.

Chet
So if I were to redo the trial with an electric stove that puts out 2500 watts, would it be easier to find the specific heat?
 
timsmith98 said:
So if I were to redo the trial with an electric stove that puts out 2500 watts, would it be easier to find the specific heat?
Yes, providing you could make sure that all the heat goes into the water and pot and none escapes to the room and stove. The difference you are trying to detect is very tiny, and the slightest error in the heat flow to the water can lead to very inaccurate results. This is really a very sensitive measurement that really needs to be made under carefully controlled laboratory type conditions.

Chet
 
timsmith98 said:

Homework Statement


For my physics IA, I am finding the specific heat capacity of water-solute mixtures and finding how the specific heat differs from that of just water alone. I have the mass of the mixture, for example baking soda and water was 914.75g and changed 175.8 degrees Fahrenheit in 9.5 minutes. I just need to know the specific heat capacity along with Q in the equation.

Homework Equations


View attachment 93337

The Attempt at a Solution


I can't find the solution because I am missing two variables: Q and C. If there's any way to find either solution, please let me know. Thank you!
BTW, the purpose of your experiments is to determine C, which is the specific heat capacity.
 
  • #10
SteamKing said:
BTW, the purpose of your experiments is to determine C, which is the specific heat capacity.
Yeah but I'm having trouble finding C because of my lack of Q. Do you know whether or not I could use the wattage of an electric burner as Q if I decided use an electric stove that puts out 2500W?
 
  • #11
timsmith98 said:
Yeah but I'm having trouble finding C because of my lack of Q. Do you know whether or not I could use the wattage of an electric burner as Q if I decided use an electric stove that puts out 2500W?
Subject to what Chet said in Post #8. You might have to arrange an experimental control, whereby you use the electric stove to heat up a known quantity of pure water.
You can measure the temperature change of the water and compare your calculation of the heat output by the stove with the amount of heat absorbed by the pure water.
 

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