- #1

AsifHirai

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## Homework Statement

A car weighs 2200 lbs, has a peak torque of 750 lb ft at 6500 RPM. Assume a CVT and racing differential keeps the power to all four wheels of the car constant and equal. What is the theoretical 0 to 60 mph time?

## Homework Equations

[itex] Fd = \frac{1}{2}m v_f ^2 - \frac{1}{2}m v_0 ^2 [/itex]

[itex] P = \frac{\tau \times \omega}{\Delta t}[/itex]

## The Attempt at a Solution

So the power output of the engine is going to be [itex] P = \frac{(750 lb ft)(6500 rpm)(2\pi rad)}{60 sec} = 510,250 \frac{ft lbs}{sec}[/itex]

The amount of work needed to get the car up to 60 mph from rest ideally would be [itex] W = \frac{1}{2}(2200 lbs)(\frac{60 mi * 5280 \frac{ft}{mi}}{3600 sec})^2 = 8,518,400 ft lbs [/itex]

Dividing those two numbers gives us 16.7 sec. I don't know if my approach is right with the work-energy theorem or if I have to use some other metric for calculating the time because I'm sure it's not that slow if the engine is pushing nearly 1000 hp...