How to find the vertical assimptote

[tex]
f(x)=\frac{1}{1+ln|x|}\\
[/tex]
[tex]
x\neq \frac{1}{e}\\
[/tex]
[tex]
x\neq \frac{-1}{e}\\
[/tex]
[tex]
lim_{x->\frac{1}{e}^+}\frac{1}{1+ln|x|}=\\
[/tex]
[tex]
lim_{x->\frac{1}{e}^-}\frac{1}{1+ln|x|}=\\
[/tex]
i cant immagine ithe values in this function
??
 

HallsofIvy

Science Advisor
41,626
821
First, 1/e is a postive number so you can just drop the absolute value.

Second, ln e-1= -1. Since ln(x) is an increasing function, if x< e-1, ln(x)< -1 and if x> e-1, ln(x)> -1. That's all you need.
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top