How to Form Butyl Propanoate and Propyl Methanoate?

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SUMMARY

The discussion focuses on the formation of butyl propanoate and propyl methanoate through Fischer esterification, a reaction between carboxylic acids and alcohols. The balanced equations for these compounds involve butanoic acid and propanol for butyl propanoate, and propanoic acid and methanol for propyl methanoate. The process includes the removal of a water molecule as a byproduct. Understanding these reactions is essential for mastering ester synthesis in organic chemistry.

PREREQUISITES
  • Fischer esterification
  • Carboxylic acids
  • Alcohols
  • Chemical equation balancing
NEXT STEPS
  • Study Fischer esterification mechanisms
  • Learn about the properties of butanoic acid and propanoic acid
  • Explore the synthesis of other esters
  • Review the role of catalysts in esterification reactions
USEFUL FOR

Chemistry students, organic chemists, and anyone interested in the synthesis of esters and understanding organic reaction mechanisms.

amesalot57
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I came across this question and I don't understand how to approach it.
Write balanced equations to show the formation of each of the following compounds. Name the reactants in each case and show clearly the removal of the water molecule.
a) butyl propanoate
b)propyl methanoate
I don't understand
 
Chemistry news on Phys.org
These are esters. Obviously you are being asked to produce them from carboxylic acids and alcohols (Fisher synthesis).

Any help?
 

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