How to get rid of units in Partition Function

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The discussion centers on deriving the partition function for a classical ideal gas in a one-dimensional harmonic potential, which involves two Gaussian integrations. The initial expression for the partition function has units that suggest it is not dimensionless, prompting concerns about normalization. Participants note that while the partition function can be made unitless using an arbitrary constant, it is not necessary in classical statistical physics, as its natural unit relates to action. The conversation highlights that constants like Planck's constant can be used in quantum contexts, but in classical mechanics, the normalization constant can be arbitrary. Ultimately, the partition function's dimensionality is less critical than its role in calculations of thermodynamic properties.
"pi"mp
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Hi guys,
I'm studying a classical ideal gas trapped in a one-dimensional harmonic potential and I first want to write out the partition function for a single particle. This, I believe, requires two Gaussian integrations, like so:

Z=\int_{-\infty}^{\infty} d\dot{x} \int_{-\infty}^{\infty}dx \,\, e^{-\beta E(\dot{x},x)}

However, we should like the partition function to be unitless. The above expression has units of (length)^2 divided by (time), as best as I can tell. Now, I know we want to divide by constant parameters of the problem to make it dimensionless. However, there is no characteristic length in this problem! The only constants we have are:

\omega = \sqrt{\frac{k}{m}}

and I can't figure out how these can be combined to cancel out the (length)^2 units in Z. How does one figure this out. Thanks :)
 
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The length scale is in deed quite arbitrary. That's why we chose the normalisation constant to be m/h with h being Plancks unit of action. In classical mechanics, this is nothing but an arbitrary constant.
 
Right, I knew I could use \hbar for quantum systems. So you're saying for classical ideal gas, I just posit some normalization constant A, claim it has the correct units, and carry it through the entire computation?
 
In quantities like energy, enthalpy, etc. the constant doesn't enter at all. In others like free energy or entropy, it enters only as an additive constant and has little relevance as we mostly measure entropy differences.
 
"pi"mp said:
However, we should like the partition function to be unitless...and I can't figure out how these can be combined to cancel out the (length)^2 units in Z. How does one figure this out.

The partition function does not have to be unitless. Its natural unit is a power of unit of action, since the integrations are over conjugated pairs ##q,p##. If you like, you can make it unitless by using arbitrary constant with appropriate dimensions, but there is little reason to do that in classical statistical physics.
 
Topic about reference frames, center of rotation, postion of origin etc Comoving ref. frame is frame that is attached to moving object, does that mean, in that frame translation and rotation of object is zero, because origin and axes(x,y,z) are fixed to object? Is it same if you place origin of frame at object center of mass or at object tail? What type of comoving frame exist? What is lab frame? If we talk about center of rotation do we always need to specified from what frame we observe?

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