How to Integrate Along Curve C_1?

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SUMMARY

The discussion focuses on integrating along the curve C_1, parametrized as {\bf p}(t) = (1+2t, 4-t) for t in [0, 1]. The derivative of the parametrization is calculated as {\bf p}'(t) = (2, -1). The integral to evaluate is expressed as ∫_{C_1} = ∫^1_0 {2√((4-t)/(1+2t)) - √((1+2t)/(4-t))} dt. The user seeks guidance on performing this integration, specifically considering rationalizing the integrands.

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Homework Statement



[PLAIN]http://img580.imageshack.us/img580/9506/linegu.jpg

The Attempt at a Solution



Parametrising the curve C_1 as follows:

{\bf p}(t) = (1-t)(1,4) + t(3,3) = (1+2t,4-t)


{\bf p}'(t) = (2,-1)

So \int_{C_1} = \bigg\{ \sqrt{\frac{y}{x}} \frac{dx}{dt} + \sqrt{\frac{x}{y}} \frac{dy}{dt} \bigg\} \;dt = \int^1_0 \bigg\{ 2\sqrt{\frac{4-t}{1+2t}} - \sqrt{\frac{1+2t}{4-t}} \bigg\} \;dt

How do I do this integration?
 
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i would attempt to rationalise the integrands
 

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