- #1
Vibhor
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I would like to know how do we solve d2x/dt2 = k' where k' is a constant i.e the task is to find x as a function of time ?
One way to approach this is to rewrite it as vdv/dx = k' where v=dx/dt and first find find v as a function of x and then rewrite v as dx/dt and then find x as a function of time .
I will present my attempt .
vdv/dx = k'
vdv= k'dx
∫vdv= ∫k'dx
v2 = 2k'x + 2C' where C' is a constant.
v=√(kx+C)
Now,v=dx/dt
dx/√(kx+C) =dt
∫dx/√(kx+C) =∫dt
x = (αt+β)2 ,where α and β are some constants.
Now ,I would like to know how do we solve the equation d2x/dt2 = k' by direct integration.
∫(d2x/dt2)dt = ∫k'dt
How to integrate the left hand side as it is a second order derivative ?
One way to approach this is to rewrite it as vdv/dx = k' where v=dx/dt and first find find v as a function of x and then rewrite v as dx/dt and then find x as a function of time .
I will present my attempt .
vdv/dx = k'
vdv= k'dx
∫vdv= ∫k'dx
v2 = 2k'x + 2C' where C' is a constant.
v=√(kx+C)
Now,v=dx/dt
dx/√(kx+C) =dt
∫dx/√(kx+C) =∫dt
x = (αt+β)2 ,where α and β are some constants.
Now ,I would like to know how do we solve the equation d2x/dt2 = k' by direct integration.
∫(d2x/dt2)dt = ∫k'dt
How to integrate the left hand side as it is a second order derivative ?
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