Integrating ODE: dv/dt=g-kv/m Step-by-Step Guide

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To integrate the ordinary differential equation dv/dt = g - kv/m, the left side can be rewritten as m dv/(mg - kv). A substitution is suggested to facilitate integration, leading to the result of (-m/k)ln|gm - kv| + C. This expression can be simplified to gm - kv = Ce^(-kt/m). The discussion emphasizes the importance of recognizing the integration technique and substitution needed for solving the ODE effectively.
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Homework Statement


How to integrate dv/dt=g-kv/m?

Homework Equations


This is ODE.

The Attempt at a Solution


dv/(g-(kv/m))=dt
Now what? I don't know how to integrate the left side.
 
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Math10 said:

Homework Statement


How to integrate dv/dt=g-kv/m?

Homework Equations


This is ODE.

The Attempt at a Solution


dv/(g-(kv/m))=dt
Now what? I don't know how to integrate the left side.
The left side can be rewritten as ##\frac{m \ dv}{mg - kv}##. There's a fairly obvious substitution you can use.
 
What substitution?
 
Never mind. I integrated and got (-m/k)ln abs(gm-kv)+C.
 
Now, how to simplify (-m/k)ln abs(gm-kv)=t+C?
 
Math10 said:
dv/(g-(kv/m))=dt
Now what? I don't know how to integrate the left side.

Are you saying you can't work \int {\frac{1}{g- \frac{kv}{m}} }dv ?Could you do something like \int (3 -5v)^{-1} dv ?
 
No, now I got it. I simplified and got gm-kv=Ce^(-kt/m).
 

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