How to measure phase difference of 2 signals using IQ demodulator

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SUMMARY

This discussion focuses on measuring the phase difference between two 40MHz signals using the AD8333 dual I/Q demodulator from Analog Devices. The method involves connecting one signal to the RF input and the other to the local oscillator (LO) input, allowing for down-conversion to DC at the I/Q outputs. The phase difference can be calculated using the formula arctan(I/Q) after obtaining the I and Q values. It is crucial to note that the AD8333 divides the LO input by 4, necessitating a PLL VCO operating at four times the input frequency for accurate measurements.

PREREQUISITES
  • Understanding of I/Q demodulation techniques
  • Familiarity with the AD8333 dual I/Q demodulator
  • Knowledge of phase difference measurement methods
  • Experience with oscilloscopes for signal visualization
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  • Research PLL VCO design for frequency multiplication
  • Learn about the Atan2 function for phase calculations
  • Explore advanced I/Q signal processing techniques
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Engineers and technicians working with RF signal processing, particularly those involved in phase measurement and demodulation using I/Q techniques.

mtxx
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for one section of my project, i need to know the phase difference between two signal.
they are both 40MHz, but out of phase by a certain angle.

i have a AD8333 board from Analog Devices,
it is a dual I/Q demodulator consist of double-balanced gilbert cell mixers.

The board has 2 RF inputs, a LO input, and 4 output (I1, I2, Q1, Q2).

I have an oscilloscope to display the results.

according to wikipedia http://en.wikipedia.org/wiki/Phase_detector#Analog_phase_detector
there is a way to measure the phase difference using IQ demoludator.in this post, https://www.physicsforums.com/showthread.php?t=336619
f95toli mentioned that:
the magnitude is just given by the norm (sqrt(I^2+Q^2)) and the phase by the phase angle (arctan I/Q)

So is this method bellow correct?
to get the phase difference of both my RF signal,
i put one the signal into RF input1, and the second signal into the LO,
then i display both the I1, and Q1 in the oscilloscope, and get an get the peak to peak magniture for both the I1 and Q1, then calculate arctan I1/Q1, to get the phase difference?
 
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mtxx said:
So is this method bellow correct?
Yes, almost. But think about it differently.

Select one signal as your reference and apply it as the local oscillator. Connect the other signal to the RF input, which will then be down-converted to DC at the IQ output. The I and Q outputs can drive the x and y axes respectively of the oscilloscope to give you a polar plot. Or you can digitise the I and Q, then compute the amplitude = Sqrt(I^2+Q^2) and the phase = Atan2(I/Q).

You will have a problem with the AD8333 because it divides the LO input by 4 to generate the internal LO quadrature signal. In order to use that chip you might run a PLL VCO at 4 times the frequency of your input signals as your LO. Then apply your two input signals to the two RF channels, use the I output from one channel, through a LP filter, to control the PLL VCO frequency. The other channel outputs, I and Q will then give you the phase difference.
 

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