How to plot complex vectors in Mathcad? (Electrical)

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To plot complex vectors in Mathcad, users must specify all points for a line trace, as it does not automatically default to the origin. Each complex number should be converted into a vector starting from zero to enable proper plotting. Alternatively, a function can be created to combine the real or imaginary part of the complex number with zero for direct plotting. The discussion also highlights the use of Mathcad's Math Style feature for better visualization. Overall, understanding these steps is crucial for accurately representing complex numbers as vectors in Mathcad.
EVriderDK
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Homework Statement



I have to plot the following complex numbers into the complex plane:
X_C=0-1350i
X_L=0+980i
R_L=100+0i
 
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Plot Re(complex number) in x-axis and Im(complex number) in y-axis
Set the trace type for each value as 'points'
 

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Thank you! How do i make them vectors on the graph? You know, a line with an arrow.
 
It is like the "line" traces does not work?

I need to tell mathcad that i want a line from 0,0 to X.C
 
EVriderDK said:
It is like the "line" traces does not work?

I need to tell mathcad that i want a line from 0,0 to X.C

Mathcad plots require that you specify all of the points on a line trace; it doesn't default to the origin. Consequently, you have to convert each of your complex numbers to a vector (with 0 as the first element) and then plot those vectors. Alternatively, you could create a function that takes a complex number, take the real or imaginary part and stacks it with zero - then plot the result directly.

See the attached worksheet for an example. It also shows how to use Mathcad's Math Style feature.
 

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Wow, thank you so much Nemo!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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