- 207

- 14

The code I have tried:

Python:

```
# The components of the vector field
F_x = y*e**x
F_y = x**2 + e**x
F_z = z**2*e**z
# The grid
xf = np.linspace(-0.15, 2.25, 8)
yf = np.linspace(-0.15, 2.25, 8)
zf = np.linspace(-0.75, 2.50, 8)
X_grid, Y_grid, Z_grid = np.meshgrid(xf, yf, zf)
# The arrows; how to deal with them?
dx = 1
#dy = ...
#dz = ...
# Standardize the arrows; In this way all arrows have the same length.
length = np.sqrt(dx**2 + dy**2 + dz**2)
dx_N = dx/length
dy_N = dy/length
dz_N = dz/length
#how to involve numpy in the process??
# Drawing the figure
fig, ax = plt.subplots(1, 1)
ax.quiver(X_grid, Y_grid, Z_grid, dx_N, dy_N, dz_N, dy, dz, cmap=plt.get_cmap('gnuplot2'))
plt.show()
```

I attach next an example I am following of a plot of another vector field (##V = \hat i + xy \hat j##).

Python:

```
# The function to be applied
def rightmember(x, y):
return x*y
# The grid
x = np.linspace(-3, 3, 25)
y = np.linspace(-3, 3, 25)
X_grid, Y_grid = np.meshgrid(x, y)
# The arrows
dx = 1
dy = rightmember(X_grid, Y_grid)
# Standardize the arrows; In this way all arrows have the same length.
length = np.sqrt(dx**2 + dy**2)
dx_N = dx/length
dy_N = dy/length
# Drawing the figure
fig, ax = plt.subplots(1, 1)
ax.quiver(X_grid, Y_grid, dx_N, dy_N, dy, cmap=plt.get_cmap('gnuplot2'))
plt.show()
```

Thank you for your help.