How to Prove Log 2 Using Riemann Sums?

tonix
Messages
18
Reaction score
0
I have been working on this problem for a while.
I am supposed to prove that <br /> log 2 = \lim_{n \rightarrow \infty} \frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2^n}.

The problem is that I have a hard time figuring out how I am supposed to prove that something is equal to a transcendental function without assuming its existence.

First, I am supposed to let
<br /> \lim_{n \rightarrow \infty} \frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2^n} = \lim_{n \rightarrow \infty} \frac{1}{n} \sum_{k=1}^n \frac{1}{1+\frac{k}{n}}

So far so good... but then I should use Riemann sums to prove that this is equal to log 2. How can I do that?
 
Last edited:
Physics news on Phys.org
your bracketing seems off, you mean the terms are like 1/(n+1), right.
 
matt grime said:
your bracketing seems off, you mean the terms are like 1/(n+1), right.

I changed the equations to latex, hope it is clear now.
 
I think you mean:

<br /> \log 2 = \lim_{n \rightarrow \infty} \frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2n}

Can you write log(2) in terms of an integral? How did you define the function log(x)?
 
shmoe said:
I think you mean:

<br /> \log 2 = \lim_{n \rightarrow \infty} \frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2n}

Can you write log(2) in terms of an integral? How did you define the function log(x)?

No, I (or better the author of the book) mean 2^n. The problem is given just like that. log(x) is just defined the usual way.
 
The reason shmoe said 2n and not 2 to the n is that you rewriting of the series in that second form does not agree with the original one.
 
matt grime said:
The reason shmoe said 2n and not 2 to the n is that you rewriting of the series in that second form does not agree with the original one.

argh...
yes. I just checked the errata and it indeed is 2n and not 2^n.
Well, given that it is 2n, does anybody have any ideas how to prove it using Riemann sums.
 
What is

\int_1^2 \frac{1}{x} dx

?

What is the Riemann sum of the above integral?
 
Data said:
What is

\int_1^2 \frac{1}{x} dx

?

What is the Riemann sum of the above integral?
um, what is n?

or do you just want to know the answer without using Riemann?
 
  • #10
for arbitrary n of course.
 
  • #11
ah... I get it now. Thanks.
 

Similar threads

Replies
2
Views
2K
Replies
3
Views
3K
Replies
16
Views
4K
Replies
2
Views
1K
Replies
7
Views
3K
Replies
7
Views
2K
Back
Top