How to prove this equation from the first attachment

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funlord
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I can's understand the fact about the equation

i can't prove the equation from the first attachment to the second attachment pls help.

Sorry for bad english
 
Attachments
  • Chain of equalities: d²x/dy² = d/dy(dx/dy) = (dx/dy)(d/dx)(dx/dy) = (dx/dy)(d/dx)(dy/dx)⁻¹ = −y''/(y')³, printed on a page.
    IMG_20160618_100935.jpg
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  • Handwritten fraction: negative y double prime over (y prime) cubed, with the numerator -y'' and denominator (y')^3.
    2.jpg
    20.8 KB · Views: 560
The second last formula is ##\frac{dx}{dy}\frac d{dx}\left(\frac{dy}{dx}\right)^{-1}##.
If we write ##y'## for ##\frac{dy}{dx}## then that is
$$\frac1{y'}\frac d{dx}\left(\frac 1{y'}\right)$$
What happens when you perform the differentiation?
 
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Thank you very much, I can understand now why it has a negative sign