How to relate P(F) with P(F') where F' is F's closure (P(F)\neq 0)

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As title:

How do you relate P(F) with P(F') where F' is F's closure.

Conditions: P(F)\neq 0 and F non-empty.

My thought is P(F)=P(F').

Is this true?
 
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Now I understand that this depends on the probability measure and of course the set F itself. there is no general conclusion that could be draw for this situation.
 
In general, since F is a subset of its closure, the probability of F is less than or equal to the probability of the closure.
 
g_edgar said:
In general, since F is a subset of its closure, the probability of F is less than or equal to the probability of the closure.

yes. thank you.
 
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