How to Solve an ODE with Mirror Functions?

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SUMMARY

The discussion focuses on solving the ordinary differential equation (ODE) given by the equation \(\frac{d^2y_{1}}{dx^2} + \frac{d^2y_{2}}{dx^2} + y_{1} + y_{2} = 0\) with the condition that \(y_{1}(x) = y_{2}(-x)\). The solution approach involves defining \(u(x) = y_{1}(x) + y_{2}(x)\) and deriving the second derivative, leading to the simplified equation \(u''(x) + u(x) = 0\). The final solutions are expressed as \(y_{1}(x) = ae^{ix} + b\) and \(y_{2}(x) = ae^{-ix} - b\), where \(a\) and \(b\) are constants.

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FrankST
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Guys,

I have an ODE like this:

The following code was used to generate this LaTeX image:


<br /> <br /> \frac{d^2y_{1}}{dx^2} + \frac{d^2y_{2}}{dx^2} + y_{1} + y_{2} = 0<br /> <br />


where, y1 (x) =y2 (-x).

Do you have any idea how to solve it?


Thanks in advance.
 
Last edited:
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Let u(x)=y1(x)+y2(x), u"(x)=y1"(x)+y2"(x)
y1"(x)+y2"(x)+y1(x)+y2(x)=0
u"(x)+u(x)=0
u(x)=aeix+ae-ix=y1(x)+y1(-x)
y1(x)=aeix+b
y2(x)=ae-ix-b
 
Last edited:
Thanks a lot.
 

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