How to Solve and Apply Boundary Conditions for the Sturm-Liouville Problem

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Homework Help Overview

The discussion revolves around the Sturm-Liouville problem, specifically focusing on rewriting a given differential equation into Sturm-Liouville form and applying boundary conditions. The original equation presented is a second-order linear differential equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore methods to rewrite the equation into Sturm-Liouville form, with some suggesting dividing through by x and recognizing patterns in the derivatives. Others discuss the implications of assuming a particular form for the solution and the challenges faced when applying boundary conditions.

Discussion Status

Several participants have offered guidance on manipulating the original equation to achieve the desired form. There is an ongoing exploration of different approaches to find a suitable solution that meets the boundary conditions, with no explicit consensus reached yet.

Contextual Notes

Participants are navigating through the constraints of boundary conditions that lead to trivial solutions, raising questions about the assumptions made in their proposed solutions.

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Homework Statement



the question is how to write the following equation to S-L form and solve the equation

Homework Equations



[tex] x^{2}y'' + xy' + \lambda^{2}y = 0 [/tex]

[tex] y(1/10) = y(2) = 0[/tex]

The Attempt at a Solution



I tried to write above equation in form

[tex] d[x^{2}y']/dx + 2\lambda^{2}y = 0 <br /> [/tex]
but it doesn't work, because it is not equal the above equation. Does anybody know how to re-write above equation in S-L form?
 
Last edited:
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Divide the original equation through by x and note that xy'' + y' = (xy')'.
 
If you have a differential equation of the form

p0(x) y'' + p1(x) y' + p2(x) y = 0

multiply it by

[tex]\frac{1}{p_0(x)}\exp\left[\int^x \frac{p_1(x')}{p_0(x')}\,dx'\right][/tex]

Then you'll be able to write the first two terms in the form you want.
 
snipez90 said:
Divide the original equation through by x and note that xy'' + y' = (xy')'.

thank you so much. it was so helpful o:)
 
vela said:
If you have a differential equation of the form

p0(x) y'' + p1(x) y' + p2(x) y = 0

multiply it by

[tex]\frac{1}{p_0(x)}\exp\left[\int^x \frac{p_1(x')}{p_0(x')}\,dx'\right][/tex]

Then you'll be able to write the first two terms in the form you want.

thanks buddy
 
hi guys,
I have another question, when I suppose that one of the solution for this problem is

[tex] y(x) = x^{m}[/tex]
actually, it doesn't work because it directs me to trivial solution and gives me the zero coefficients after applying the boundary conditions, do you have any idea about the supposition of yj(x) for applying the boundary condition and then calculating the coefficients.

many thanks if you give me a hint
 

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