How to Solve Fractional Equations with Squared Variables?

[homegrown898]

Because I can't write squared, if x is squared, I will just write it like this: xsquared

x/x +2 MINUS x/xsquared - 4 = x+3/x+2

I get an LCD for each fracton and then I subtract getting this:

xsquared - 2x MINUS x/xsquared - 4 = (x+3)(x-2)/xsquared - 4

What do I do now?

If you don't understand this just ask me to scan it

 

[Data]

I suppose you mean

\frac{x}{x+2} - \frac{x}{x^2-4} = \frac{x+3}{x+2} \Longrightarrow \frac{x^2 - 3x}{x^2 - 4} = \frac{(x+3)(x-2)}{x^2 - 4}

which is fine.

 

[Moo Of Doom]

If you don't understand this just ask me to scan it

Or just learn LaTeX.

I'm not quite sure what you mean. I surmise it is something like this:

<br /> \frac{x}{x+2}-\frac{x}{x^2-4}=\frac{x+3}{x+2}

If it's not right, let me know.

EDIT: Yarr, Data got there before I did...

 

[homegrown898]

I suppose you mean

\frac{x}{x+2} - \frac{x}{x^2-4} = \frac{x+3}{x+2} \Longrightarrow \frac{x^2 - x}{x^2 - 4} = \frac{(x+3)(x-2)}{x^2 - 4}

which is fine.

Moo, that was right what you posted

And that is where I got but the instructions are to solve

Is that a solution to it?

 

[Data]

Note that there is a small error in the thing you quoted, which I've corrected now.

To solve, multiply x^2-4 through both sides, expand on the right, and see what you get.

 

[homegrown898]

Note that there is a small error in the thing you quoted, which I've corrected now.

To solve, multiply x^2-4 through both sides, expand on the right, and see what you get.

I don't want to learn Latex right now because it will take too long but I'll learn it for the future.

This is what I'm getting:

xsquared - 2x - x = xsquared + x - 6

I subtract xsquared on each side to cancel them out getting:

-2x - x = x - 6

I then subract x from each side getting

-3x - x = -6

Then I subract the x

-4x = -6

Did I mess up?

 

[Moo Of Doom]

Did I mess up?

Looks right to me.