MHB How to Solve Non-Linear Equations of 3 Variables Using Newton-Raphson Method?

ra_forever8
Messages
106
Reaction score
0
The three non-linear equations are given by
\begin{equation}
c[(6.7 * 10^8) + (1.2 * 10^8)s+(1-q)(2.6*10^8)]-0.00114532=0
\end{equation}
\begin{equation}
s[2.001 *c + 835(1-q)]-2.001*c =0
\end{equation}
\begin{equation}
q[2.73 + (5.98*10^{10})c]-(5.98 *10^{10})c =0
\end{equation}
Using the Newton-Raphson Method solve these equations in terms of $c$,$s$ and $q$.=> It is really difficult question for me because i don't know very much about the Newton-Raphson Method and also these non-linear equations contain 3 variables.I have try by applying the Newton-Raphson method to each equations:-
\begin{equation}
f(c,s,q)=0= c[(6.7 * 10^8) + (1.2 * 10^8)s+(1-q)(2.6*10^8)]-0.00114532
\end{equation}
\begin{equation}
g(c,s,q)=0= s[2.001 *c + 835(1-q)]-2.001*c
\end{equation}
\begin{equation}
h(c,s,q)=0= q[2.73 + (5.98*10^{10})c]-(5.98 *10^{10})c
\end{equation}
now i guess i need to work out $f'(c,s,q), g'(c,s,q), h'(c,s,q)$ but i don't know how?and after working out $f'(c,s,q), g'(c,s,q), h'(c,s,q)$ . After that i think i need to use Newton-raphson iteration:$c_{n+1}= c_n - \frac{f(c,s,q)}{f'(c,s,q)}$ but the $f(c,s,q)$ and $f'(c,s,q)$ contains the $s$ and $q$.

Similarly, for $s_{n+1}= s_n - \frac{g(c,s,q)}{g'(c,s,q)}$ will have $g(c,s,q)$ and $g'(c,s,q)$ containing the $c$ and $q$.$q_{n+1}= q_n - \frac{h(c,s,q)}{h'(c,s,q)}$ will have $h(c,s,q)$ and $h'(c,s,q)$ containing the $c$.so am i not sure what to do please help me. to find the values of $c,s,q$.
 
Mathematics news on Phys.org
grandy said:
The three non-linear equations are given by
\begin{equation}
c[(6.7 * 10^8) + (1.2 * 10^8)s+(1-q)(2.6*10^8)]-0.00114532=0
\end{equation}
\begin{equation}
s[2.001 *c + 835(1-q)]-2.001*c =0
\end{equation}
\begin{equation}
q[2.73 + (5.98*10^{10})c]-(5.98 *10^{10})c =0
\end{equation}
Using the Newton-Raphson Method solve these equations in terms of $c$,$s$ and $q$.=> It is really difficult question for me because i don't know very much about the Newton-Raphson Method and also these non-linear equations contain 3 variables.I have try by applying the Newton-Raphson method to each equations:-
\begin{equation}
f(c,s,q)=0= c[(6.7 * 10^8) + (1.2 * 10^8)s+(1-q)(2.6*10^8)]-0.00114532
\end{equation}
\begin{equation}
g(c,s,q)=0= s[2.001 *c + 835(1-q)]-2.001*c
\end{equation}
\begin{equation}
h(c,s,q)=0= q[2.73 + (5.98*10^{10})c]-(5.98 *10^{10})c
\end{equation}
now i guess i need to work out $f'(c,s,q), g'(c,s,q), h'(c,s,q)$ but i don't know how?and after working out $f'(c,s,q), g'(c,s,q), h'(c,s,q)$ . After that i think i need to use Newton-raphson iteration:$c_{n+1}= c_n - \frac{f(c,s,q)}{f'(c,s,q)}$ but the $f(c,s,q)$ and $f'(c,s,q)$ contains the $s$ and $q$.

Similarly, for $s_{n+1}= s_n - \frac{g(c,s,q)}{g'(c,s,q)}$ will have $g(c,s,q)$ and $g'(c,s,q)$ containing the $c$ and $q$.$q_{n+1}= q_n - \frac{h(c,s,q)}{h'(c,s,q)}$ will have $h(c,s,q)$ and $h'(c,s,q)$ containing the $c$.so am i not sure what to do please help me. to find the values of $c,s,q$.

Write your system as a vector equation in a vector variable, you want a solution of the system:
$${\bf{f}}({\bf{x}})={\bf{0}}$$

The NR iteration for this is:

$${\bf{x}}_{n+1}={\bf{x}}_n-[{\rm{J}}({\bf{x}}_n)]^{-1}{\bf{f}}({\bf{x_n}})$$

where ${\rm{J}}({\bf{x}})$ is the matrix with $i.j$ th element equal to $ \dfrac{\partial {\bf{f}}_i}{\partial{\bf{x}}_j}$
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top