How to Solve Projectile Motion Problems in One or Two Lines

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Projectile motion problems can be efficiently solved in one or two lines by prioritizing key parameters over time. The discussion introduces two main equations that connect five essential variables: horizontal displacement, vertical displacement, initial horizontal velocity, initial vertical velocity, and final vertical velocity. By treating these variables as a system of equations, one can derive the time of flight using the formula Δx/v0x. Additionally, three auxiliary shortcut equations are provided to streamline the process of identifying parameters. This method offers advantages over traditional approaches, making it a valuable strategy for solving projectile motion problems.
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Introduction
We show how one can solve most if not all, introductory-level projectile motion problems in one or maybe two lines. To this end, we forgo convention.  We demote clock time ##t## to a parameter of secondary importance and ditch the independence of motion in the vertical and horizontal directions.
Starting from the first principles, we develop two primary equations that relate five “basic” parameters to each other: ##\Delta x##, ##\Delta y##, ##v_{0x}##, ##v_{0y}## and ##v_y## (standard definitions).  We view the solution of projectile motion problems as equivalent to solving a system of five equations with the five basic parameters as the five unknowns.  Once the system is solved, the time of flight, if one must have it, is just the ratio ##\Delta x/v_{0x}##.
To sharpen the implementation of the primary equations, we recombine them to derive three auxiliary shortcut equations that facilitate the identification of equation parameters with given variables.  Finally, we...

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This is a nice approach. It does seem to have some advantages over the standard approach.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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