How to solve the trigonometric equation sin(x) = x/2?

  • Thread starter Thread starter prasannapakkiam
  • Start date Start date
  • Tags Tags
    Trigonometric
AI Thread Summary
To solve the trigonometric equation sin(x) = x/2, one can identify the intersections of the functions f(x) = sin(x) and g(x) = x/2. While determining the number of solutions is straightforward using graphical analysis, finding the exact solutions requires more rigorous methods. The discussion highlights that there are three intersection points, including the common solution at x = 0. Newton's method is recommended as an efficient numerical approach to find these solutions quickly, especially under time constraints. This method is noted for its accuracy, making it suitable for scholarship exam preparation.
prasannapakkiam
How would one go about solving sin(x) = x/2
I.e. the intersections of
f(x)=sin(x)
&
g(x)=x/2

I can rigorously solve this by going to each individual period and finding the intersections. But is there a better way?
 
Mathematics news on Phys.org
You can find the no. of solutions easily enough using graphs, but getting the actual solution, would require rigour.
 
This is going to do my scholarship exam on Friday. I was only notified today that I was selected. Although I knew most of the requirements prior to this, I did not know about trigonometric equations such as this. I cannot afford to draw graphs - time constraints are not going to do me favours. I know for sin(x)=k, there is a simple general solution rule. But as for kx; are there any quicker methods?
 
Do you want to know the exact intersections or the number of intersections? If it's the number, it's fairly easy. The maxima and minima of sin x all have y = 1 and y = -1. The function x/2 is equal to 1 at x = 2 and - 1 at x = -2. Since the pi/2< 2 <pi, then it has to cross sin x at two points on the positive x-axis (picture this in your mind: the line has to cross the "mountain" between 0 and pi). Same applies to -2 > -pi. There are in total 3 intersection points (x = 0 is common to the positive and negative sides of the x axis).
 
Yes I suppose knowing the number of solutions may be helpful. However, the values are also expected...
 
Then, there exist no analytical method. Apart from the obvious x = 0 solution, the others have to be found by other method. Are you familiar with Newton's method?
 
No I am not aware of Newton's method
 
Then learn about it, you haven't got much time! Though, it's strange that they would ask you this kind of question...
 
Last edited:
Wow! I have just learned it! It is quite accurate with just 3 steps. Since they expect 3 s.f. it is perfect. Thanks.
 
Back
Top