Hi, Q 1. ( e ^ y/x - y/x e ^ y/x + 1 / 1 + x^2 ) dx + e ^ y/x dy = 0 Ans. I know its Homogeneous sub, y = ux, then, dy / dx = u dx + x du I did this, and got to the point, e^u dx + 1 / ( 1 + x^2) dx + x. e^u du = 0 How can we separate this now? Q 2. y dx + ( 2x - y e^y ) dy = 0 I think we can use exactness, here M = y My = 1 N = 2x - y e^y Nx = 2 Not exact, so, Integrating Factor would be : e ^ Integral My - Nx / N Is this right. Integrating factor is getting to complicated to multiply the eqn, with. Any better way of doing this. Q 3. ( 2x + tany) dx + ( x - x^2 tany ) dy = 0 I think here too, exactness, may be used, but any better way, if possible.