Mastering Equation Solving: 3 Ways to Simplify Complex Equations

  • Thread starter yoyochan
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In summary, the conversation discusses a set of equations involving the variables t, x, y, and z. The RHS of two lines are identical, and there are potential solutions that can be found using matrices. The origin and constraints of these equations are unknown, and it is recommended to try solving them using Wolfram Alpha.
  • #1
yoyochan
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(3*10^8 t - 19288.47)^2 = (x-18167.44)^2 + (y-38037.28)^2 + (z-433.35)^2
(3*10^8 t - 17862.46)^2 = (x-40607.42)^2 + (y-11317.32)^2 + (z-5.077)^2
(3*10^8 t - 69656.18)^2 = (x-40607.42)^2 + (y-11317.32)^2 + (z-5.077)^2
(3*10^8 t - 14143.42)^2 = (x-24729.37)^2 + (y-34126.78)^2 + (z-930.27)^2
 
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  • #2
yoyochan said:
(3*10^8 t - 19288.47)^2 = (x-18167.44)^2 + (y-38037.28)^2 + (z-433.35)^2
(3*10^8 t - 17862.46)^2 = (x-40607.42)^2 + (y-11317.32)^2 + (z-5.077)^2
(3*10^8 t - 69656.18)^2 = (x-40607.42)^2 + (y-11317.32)^2 + (z-5.077)^2
(3*10^8 t - 14143.42)^2 = (x-24729.37)^2 + (y-34126.78)^2 + (z-930.27)^2
You are wanting to solve these simultaneously? Where did these come from?

Are you sure the RHS of two lines is supposed to be identical?
 
  • #3
It is strange equations..
But I think you can do it by matrices ..
Can't you!
 
  • #4
Maged Saeed said:
It is strange equations..
That's why I'm curious to know where they arose.

Are there any other constraints on the solutions?

But I think you can do it by matrices ..
Have you looked into this, and tried solving by any means? Others are more inclined to offer help if they can see you have at least made some attempt at solving it by your own effort.

Do you have in mind how many sig figs you would like in the answers?

If all you are interested in are the solutions, have you tried wolfram alpha?
 

1. How do I know which method to use to solve an equation?

The method you use to solve an equation depends on the type of equation. For linear equations with one variable, you can use inverse operations or the balance method. For quadratic equations, you can use factoring, the quadratic formula, or completing the square. For systems of equations, you can use substitution or elimination. It is important to read the problem carefully and determine the type of equation before choosing a method.

2. Can I solve an equation by guessing and checking?

You can solve some equations by guessing and checking, but this method is not reliable and can be time-consuming. It is better to use a systematic method, such as substitution or elimination, to solve equations.

3. How do I check if my solution is correct?

To check if your solution is correct, you can substitute the value you found for the variable back into the original equation. If the equation is true, then your solution is correct. You can also use a graphing calculator to graph the equation and see if the solution is the point where the graph intersects the x-axis.

4. What should I do if I get a negative or imaginary solution?

If you get a negative or imaginary solution, it means that there are no real solutions to the equation. This can happen with quadratic equations that do not have any real roots. In this case, you can state that there are no solutions or that the solution is "no solution" or "undefined".

5. Can I solve an equation with more than one variable?

Yes, you can solve equations with more than one variable, also known as systems of equations. These equations have more than one unknown variable and can be solved using substitution or elimination. It is important to have the same number of equations as variables in order to solve the system.

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