Solving Ri(t)+Ld$\frac{di(t)}{dt}=V_{m}sin(wt+\theta)

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Can anyone help me with this?
Ri(t) + L\frac{di(t)} {dt}=V_{m}sin(wt+\theta)
 
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Hint:
What is the integrating factor here?
 
\exp\int\frac{R}{L}dt?
 
Which can be written more simply as..:?(assuming R, L constants, that is)
 
\exp\int{x}dt
 

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