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How to take sin^2 out and leave theta

  1. Apr 29, 2015 #1
    This is a small portion of a bigger physics problem I am trying to solve, but I can't get passed this little integrand reformulation.

    How does this

    ∫(sinθ/cosθ)d(sin2θ)

    Become

    ∫[sinθ(2sinθcosθ)/cosθ]dθ

    Basically, how is the sin2 taken out of the d(sin2θ) and the θ left in the dθ?

    Thanks
     
  2. jcsd
  3. Apr 29, 2015 #2

    Dick

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    Science Advisor
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    ##d(f(\theta))=\frac{df(\theta)}{d\theta} d\theta##. Is that enough?
     
  4. Apr 29, 2015 #3
    It is more than enough

    Thanks
     
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