I How to understand Plutonium enrichment in the graph

  • I
  • Thread starter Thread starter Neutroniclad
  • Start date Start date
  • Tags Tags
    Graph
Neutroniclad
Messages
14
Reaction score
0
http://ncsp.llnl.gov/ARH-600/files/pdfs/III.A.4-2.pdf
For a certain fixed density (let's say 1g/cm3) different enrichment corresponds with different cylinder diameter
20% wt 12.0in
15% wt 11.2in
10% wt 10.4in
5% wt 9.6in
0% wt 8.4in
Why the decrease of enrichment result in a smaller critical diameter?
 
Physics news on Phys.org
I think Pu-240 isn't fissionable or not as easily while it may absorb neutrons. Hence the less Pu-240, the less the critical diameter
 
DrDu said:
I think Pu-240 isn't fissionable or not as easily while it may absorb neutrons. Hence the less Pu-240, the less the critical diameter
Thank you for your opinion.
So you mean the number here refers to the enrichment of Pu-240? i.e. 5%wt means 5% Pu-240 with 95% Pu-239.
If so, does 0%wt refers to 100% Pu-239? Or is there something else in the plutonium?
 
Neutroniclad said:
So you mean the number here refers to the enrichment of Pu-240?
Yes, it says so. But I can't judge from only the graph that the rest is Pu-239. However, I would suppose so.
 
  • Like
Likes Neutroniclad
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top