How to use AM-GM to find the minimum of a function

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To find the minimum value of the function f(x) = 3(x + 1/x) using the AM-GM inequality, recognize that the function can be expressed as a sum of two non-negative terms. Applying the AM-GM inequality, we have (x + 1/x)/2 ≥ √(x * 1/x), which simplifies to (x + 1/x) ≥ 2. Multiplying by 3 gives f(x) ≥ 6, indicating that the minimum value of f(x) is 6. This minimum occurs when x = 1, confirming that AM-GM effectively identifies the minimum without calculus.
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Homework Statement


Let ##\displaystyle f(x) = 3 \left( x + \frac{1}{x} \right)##. Use AM-GM to find the minimum value.

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The Attempt at a Solution


I know how to find the minimum value using calculus: we take the derivative, set it to zero,then find the critical points. Then we can use the second derivative to distinguish between maxima and minima.

However, I am not sure how to use the AM-GM inequality to do this, which is that ##\displaystyle \frac{x+y}{2} \ge \sqrt{xy}## for all non-negative real numbers x and y
 
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Your f(x) includes the sum of two elements; the AM-GM formula includes a sum. Try something really obvious on that basis.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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