How to Use Duality Property for Finding Fourier Transform of sin x / x?

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To find the Fourier transform of sin x / x, the duality property of Fourier transforms can be utilized effectively. The integral involves evaluating sin x / x multiplied by the exponential function, but traditional methods like Jordan's Lemma may not apply. The hint suggests using the relationship between sinc functions and square waves, indicating that the Fourier transform of a square wave can assist in this evaluation. Understanding the time domain representation can clarify the process, even if it initially seems confusing. This approach provides a pathway to compute the desired Fourier transform accurately.
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Hi, how do I find the Fourier transform of this function sin x / x, i.e.,

f* = Integral( sin x / x * exp( i*w*x) dx from -infinity to +infinity ).

I've been using Jordan's Lemma up to this point, but it doesn't seem to
apply here as a way to evaluate the integral.

Thanks for any help.
 
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Hint: Use the duality property of Fourier transforms. Remember that d*sinc(w) = d*sin(pi*w*d) / (n*pi*w*d) is the Fourier transform of a square wave in the time domain with duty cycle d.

Edit: Fixed some things. If the time domain part confuses you, ignore it; I learned this stuff primarily from a signals & systems perspective.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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