How to use geometrical interpretation to prove an inequality?

[stanley.st]

Homework Statement

Prove that

\frac{1-h}{2}<\sum_{k=1}^{n}x_{2k}(x_{2k+1}-x_{2k-1})<\frac{1+h}{2}

where 0=x_1<x_2<\cdots<x_{2n+1}=1 such that x_{k+1}-x_{k}<h for 1\le k\le 2n

Homework Equations

How to prove? :-)

The Attempt at a Solution

I need to prove
\left|-1+2\sum_{k=1}^{n}x_{2k}(x_{2k+1}-x_{2k-1})\right|<h

\left|-1+2\sum_{k=1}^{n}x_{2k}(x_{2k+1}-x_{2k-1})\right|=\left|-1+2\sum_{k=1}^{n}x_{2k}(x_{2k+1}-x_{2k}+x_{2k}-x_{2k-1})\right|\le\left|-1+4h\sum_{k=1}^{n}x_{2k}\right|

 

[boboYO]

Draw a diagram. Each term in the sum corresponds to an approximation of the area under the graph in the interval (x_{2k-1},x_{2k+1}). For each interval, find the difference between
[the approximation] and [the exact value for the area under the graph in the interval (x_{2k-1},x_{2k+1})]Add up the differences and you will get your result.