How to Use Log Rule for Integrals with Radical Expressions?

  • Thread starter Thread starter fluxions22
  • Start date Start date
  • Tags Tags
    Integrals Log
Click For Summary

Homework Help Overview

The discussion revolves around evaluating the integral of x divided by the square root of (9 - x²). Participants are exploring the application of logarithmic rules and substitution methods in the context of integral calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants question the relevance of the logarithmic rule presented by the original poster and suggest alternative methods, including factoring and substitution. There is a focus on clarifying the steps needed to approach the integral correctly.

Discussion Status

The discussion is ongoing, with participants providing suggestions for different approaches to the integral. Some guidance has been offered regarding factoring and substitution, but there is no consensus on a specific method yet.

Contextual Notes

There appears to be a misunderstanding regarding the application of the logarithmic rule, and participants are addressing the need for more detailed work in the solution process. The original poster's initial attempt does not align with the integral's requirements.

fluxions22
Messages
10
Reaction score
0

Homework Statement


integral of x/square root of 9- x^2


Homework Equations



1/x dx= ln |x| + c

The Attempt at a Solution


3 ln|x| + c
 
Physics news on Phys.org
You need to show more work. At this point, it looks like you're just guessing.

So you have the integral

I=\int \frac{x}{\sqrt{9-x^2}}\,dx

right? I don't see how

\int \frac{dx}{x} = \ln |x| + c

applies at all.
 
Try factoring out a 9 in the denominator in the square root. It should be somewhat obvious from there what you need to do.
 
physicsman2 said:
Try factoring out a 9 in the denominator in the square root. It should be somewhat obvious from there what you need to do.
A simpler approach is to use an ordinary substitution. Using this approach you don't need to factor anything out of the radical.
 
Mark44 said:
A simpler approach is to use an ordinary substitution. Using this approach you don't need to factor anything out of the radical.

Oh whoops, I didn't see the x in the numerator. I thought there was only a 1 in the numerator, which is why I thought that at first. You're right.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 54 ·
2
Replies
54
Views
16K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K