# How we see image inside the concave mirror when object is beyond C?

• Deepak Singh Ola
In summary, when using a concave mirror, the traditional ray diagrams show a real and inverted image formed between the centre of curvature and the focal point. However, when looking directly into the mirror and removing the screen, an inverted image can be seen inside the mirror. This can be explained using ray diagrams, which can be found through a Google search for "Concave Mirror Ray diagram." This effect is also obtainable with convex lenses, where either a real or virtual image can be formed depending on the object's position. With convex mirrors or concave lenses, only one image is formed regardless of the object's position. It should be noted that the diagram in question may not accurately portray the inverted image behind the mirror, as confirmed by
Deepak Singh Ola
In concave mirror, when object is beyond C ( centre of curvature) our traditional Ray diagrams show a real and inverted image formed between C and F. But at the same time, if we look directly into the mirror and remove the screen, we see an inverted image which appears to be inside the mirror. Explain this image using Ray diagram.

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Hi and welcome to Physics Forums.
I am not sure what your question is - and what is "the screen"?
Have you tried a Google search for "Concave Mirror Ray diagram"? There is no point in my giving you a home made ray diagram when there are thousands available on the Web but you will notice something about concave mirrors. Depending on where the object is relative to the mirror centre of curvature (object distance and r) you can get a real image 'inside' the mirror or a virtual image behind the mirror. If the object is at the centre of curvature, all rays from the object will come back and hit the object.

This effect is also obtainable with a convex Lens, where either a real or virtual image can be formed. Again, Google (Images) is your friend.

With convex mirrors or concave lenses, there is only one image is formed, wherever the object is.

PS I don't agree with your diagram showing an inverted image behind the mirror. Google will put you right. (Thy Hyperphysics website)

This is the ray diagram of this situation... This explains the real image formed outside the mirror... But when we look into the mirror and as you said, real image can be seen inside the mirror and it's true.. but how to explain this image inside the mirror Using ray diagram?

## 1. How does a concave mirror create an image when the object is beyond the center of curvature?

When an object is placed beyond the center of curvature (C) of a concave mirror, the reflected rays converge and form an inverted real image. This is due to the fact that the concave shape of the mirror causes the reflected rays to converge towards a focal point, resulting in an image being formed.

## 2. Why is the image formed by a concave mirror inverted when the object is beyond C?

The inversion of the image is a result of the way light rays reflect off the concave mirror. The top of the object is reflected downwards and the bottom of the object is reflected upwards, causing the image to appear inverted. This is known as the principle of reversibility of light.

## 3. How does the distance between the object and the mirror affect the size of the image?

The distance between the object and the concave mirror affects the size of the image through the magnification equation: M = -v/u, where M is the magnification, v is the image distance, and u is the object distance. As the object moves further away from the mirror, the image size decreases.

## 4. Can a concave mirror create a virtual image when the object is beyond C?

No, a concave mirror can only create a virtual image when the object is located between the mirror and the focal point. When the object is beyond C, the reflected rays converge and form a real image.

## 5. Why is the image formed by a concave mirror beyond C larger than the object?

The magnification equation (M = -v/u) also explains why the image formed by a concave mirror is larger than the object when the object is beyond C. Since the image distance (v) is negative and the object distance (u) is positive, the magnification will be greater than 1, resulting in a larger image.

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