How were tangent terms derived in solving for eqn (2) in a second-order circuit?

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paulmdrdo
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Homework Statement
Find the expression for ##v(t)##
Relevant Equations
SEE ATTACHED PHOTO
I was trying to follow the solution for this problem and got stuck in the last portion of the solution. I encircled the part that I did not understand. I can't figure out how the solver was able to come up with tangent terms. Please enlighten me. TIA
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The author equated eqn (2) to 0
then extracted (and divided both sides by) the common factor 5(cos 21.749t)
 

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