JT Smith
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There have been apps that can transfer the notes from an instrument to Midi code for years. I haven't understood how the (now revealed) requirement of the OP wouldn't be met by this.JT Smith said:I thought you wanted to know how much the frequency changed when you stretched the string by 0.14mm? If what you really want to do is recognize notes there is likely already software that will do that.
Do you not have an electric guitar available? That's seriously all you need for the biggest part of your project (as you have stated it).kokes said:I don't have a pickup around to test, and we are being locked down.
Well, the frets on my guitars definitely show wear. It seems reasonable that strings suffer as well.JT Smith said:I just read one guy's opinion that the strings become uneven over time and that messes up intonation. He didn't explain why though.
They get corroded over time - even when not being played - but sweaty fingers spoil them. 'Good' players wipe down and lubricate strings after playing. Instrumentalists have a whole stock of well founded and unfounded opinions about how to improve. There's no end to it.Paul Colby said:Well, the frets on my guitars definitely show wear. It seems reasonable that strings suffer as well.
That's an accurate description of the whole of life.kokes said:I always think it is done and fix the last bug only to discover three more bugs.
Paul Colby said:Well, the frets on my guitars definitely show wear. It seems reasonable that strings suffer as well.
Good question. When testing intonation one is comparing vibration of the full string to half the string under slightly more tension. The part vibrating when fretted is the half I'd expect to be the least worn. Could be the change in tension between un-fretted and fretted effectively decreases because the cross section of the string is eroded?JT Smith said:Why would uneven wear cause the string be flat at the twelfth fret?
The wear I'm thinking of is at each fret location. It would be like cutting small flexures at every fret. This would have the effect of reducing the average spring constant for the string.JT Smith said:If I'm doing the calculation correctly you'd need to lose about 1mg (about 0.1 cubic millimeter) from a .010 steel string to make it go flat by a few cents.
pred [1.4404296789560043, 93.62769589051987, 0.24132288857279646]
po [1.440429678909144, 93.62769588747395, 0.24132288857104095]
pred [1.6666666594460722, 108.33306298894432, 0.27922557999291575]
po [1.6666666593975659, 108.3330629857914, 0.2792255799908845]
pred [1.8359374919842715, 119.33563969474247, 0.3075844279608739]
po [1.8359374919345335, 119.3356396915095, 0.3075844279586363]
pred [1.9966125401166401, 129.77949180603417, 0.3345031781814851]
po [1.996612540065733, 129.7794918027252, 0.3345031781790516]
pred [2.18749999250063, 142.18714530153696, 0.3664835740720298]
po [2.187499992448334, 142.18714529813775, 0.36648357406936366]
pred [2.330322257526184, 151.47056940169833, 0.39041135204829086]
po [2.330322257472849, 151.47056939823153, 0.39041135204545063]
pred [2.4999999930012002, 162.49959473250186, 0.4188383706173862]
po [2.4999999929466306, 162.49959472895483, 0.41883837061433915]
Paul Colby said:The wear I'm thinking of is at each fret location. It would be like cutting small flexures at every fret. This would have the effect of reducing the average spring constant for the string.
because the tension is determined by the full string not just the lower half. Lower tension lower pitch.JT Smith said:Why do you think that a reduced spring constant for the upper half of the string would cause the lower part to go flat?
Paul Colby said:because the tension is determined by the full string not just the lower half. Lower tension lower pitch.
I'm having a hard time with the magnitude of the fret corrections you're calculating. They seem disproportionately large and discontinuous fret to fret.kokes said:True temperament frets, elliptical fretboard, fanned scalloped neck.
We're talking about the change in pitch added by the tension incurred by pressing the string to the 12'th fret. Initially the bridge is adjusted such that the twelfth harmonic matches in pitch with the pitch obtained when the string is pressed into the 12'th fret. The strings age and wear. The wear reduces the string material at each fret as time passes. The stiffness at these wear points is reduced. Now the string looks like many springs of slightly differing stiffness connected in series.JT Smith said:I don't get it. If you lower the tension won't the string be out of tune?
Paul Colby said:Since the stiffness has been reduced at the wear points, the tension increase by pressing into the fret is now less than it was initially when the guitar intonation was set. This causes the note to be flat.
Yes.kokes said:I was trying to search but found no results.
Is there a way to calculate how frequency will change if I stretch a string by certain amount (0.14 mm in my case)?[
Use the formula for the frequency of a string under tension. Several things to consider. As you stretch the string, the mass density will decrease slightly. Is this important for your purpose? If so, look up Poisson's ratio.I found out I can measure its frequency once stretched, but no results as of how to estimate new frequency ahead of the time. I know a speed of string can be calculated from its weight, length and tension, but that doesn't seem to get me anywhere:
The metal work hardens, plust oxidation plus grime at random spots. My strings always feel really slinky before stretching them out and get a bit stiffer to bend to the same pitch. Supposedly, boiling them will somewhat restore them, which I assume is some sort of annealing, but it seems too low a temperature for that. I've personally never tried that, but that's the lore. Maybe it just removes the grime and oxidation well.Paul Colby said:The properties of strings change with time. I find it takes about a day for a new set to stop stretching. My guess is they lose stiffness as the age.
There are different lengths to consider. One is the scale length, which is the distance from the nut to the bridge. The other is the total length of the string, since the tension in the entire string changes, so to figure out what are younge in tension you need, you have to consider the length of the string from the tuners to the tailpiece.Why do you think that a reduced spring constant for the upper half of the string would cause the lower part to go flat?
I hope you have the proper tools for this. If you are using a scalloped neck, the reason for scalloping is that you do not push the string to fretboard. If you try to set it up by pushing the string all the way to the fretboard, you will never get it in tune across the fretboard. With scalloping, the idea is to just press lightly enough for the string to make contact with the fret. You have to have a very light touch to play that in tune.kokes said:I am catching the last minutes of a weekend, I've got much work next week. Here is what I have so far. First picture shows ellipse, if you look closely. Upper spikes of teeth count. Second picture is 3d view. True temperament frets, elliptical fretboard, fanned scalloped neck.
It's not the increase in length he's discussing; it the change in string modulus, which is affected by both sections of the string. Your finger pressure may have a small effect on that because a metal clamp would isolate the two sections but your finger is not a Capo.JT Smith said:The string elongates by only a tiny amount,
There a few basics that you need to sort out. The 'ellipse' theory only predicts the incremental increase in length (= extension) and the tension is incremental too.kokes said:The elliptical theory suggests that open string has no tension, which is not true
sophiecentaur said:It's not the increase in length he's discussing; it the change in string modulus, which is affected by both sections of the string. Your finger pressure may have a small effect on that because a metal clamp would isolate the two sections but your finger is not a Capo.
JT Smith said:What I'm saying is that because the elongation is so small the resultant increase in pitch is too small for this to make sense. The string constant would have to change by far more than is likely.