- #1
aaa59
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if A={1,2,3}
f:A-> A = {(1,2),(2,3),(3,1)}
g:A->A = {(1,2),(2,1),(3,3)}
how would we calculate (f O g)?
f:A-> A = {(1,2),(2,3),(3,1)}
g:A->A = {(1,2),(2,1),(3,3)}
how would we calculate (f O g)?
The formula for calculating (f O g) is (f O g)(x) = f(g(x)), where f and g are functions and x is the input value.
The domain of (f O g) is determined by the domain of g, as g is the input for f. The range of (f O g) is determined by the range of f, as f(g(x)) will output values within its range.
No, (f O g) cannot be calculated without knowing the specific functions f and g. The formula for (f O g) requires the functions to be inputted.
The order of the functions matters in the calculation of (f O g). The function g will be applied first to the input value, and then the resulting output will be used as the input for f.
Sure, let's say f(x) = x^2 and g(x) = 2x+1. To calculate (f O g), we first plug in g(x) into the input of f(x), which gives us f(g(x)) = (2x+1)^2. Then we can simplify to get (f O g)(x) = 4x^2 + 4x + 1.