Hp/Kw required to move 1.5L/m of diesel fuel at 17.2 Bar?

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Discussion Overview

The discussion revolves around calculating the horsepower (Hp) or kilowatts (kW) required to move 1.5 liters per minute of diesel fuel at a pressure of 17.2 Bar. The context is practical, focusing on real-life applications of fluid dynamics and power calculations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • Some participants assert that power can be calculated using the formula: power equals pressure times volumetric flow rate.
  • There is a question about the units of power, specifically whether the result is in kilowatts (kW).
  • One participant emphasizes the need to choose appropriate units and perform necessary conversions, indicating that kW is equivalent to 1000 watts.
  • Another participant expresses frustration over the discussion's complexity, seeking a straightforward answer without delving into detailed unit conversions.
  • Responses indicate a desire for participants to engage in the learning process rather than simply receiving answers, highlighting a tension between seeking quick solutions and understanding the underlying principles.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the approach to finding the answer, with some advocating for a detailed understanding of units and conversions, while others prefer a more direct response. The discussion remains unresolved as no consensus on the calculation method or final answer is reached.

Contextual Notes

Participants express varying levels of familiarity with units of power and fluid dynamics, leading to assumptions and misunderstandings about the expected knowledge base. The conversation reflects a mix of technical inquiry and frustration over the complexity of the topic.

Chincha40
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How much Hp/Kw required to move 1.5L/m of Diesel fuel at 17.2 Bar? Please note this is for a real life problem.
 
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Chincha40 said:
How much Hp/Kw required to move 1.5L/m of Diesel fuel at 17.2 Bar? Please note this is for a real life problem.
Power is pressure times volumetric flow rate.
 
russ_watters said:
Power is pressure times volumetric flow rate.
So what units of power is that in? Kw?
 
Chincha40 said:
So what units of power is that in? Kw?
You'll need to pick the units and do the proper conversions. So, what is a kW?
 
russ_watters said:
You'll need to pick the units and do the proper conversions. So, what is a kW?
kW=Kilowatt that is 1000 watts. Sorry I assumed everything here was metric or nothing and that people here would know units of power. I need to stop making assumptions. It seems most of this forum isn't really tuned to these sort of questions by looking at the popular topics discussed.
 
Chincha40 said:
kW=Kilowatt that is 1000 watts.
What is a watt?
Sorry I assumed everything here was metric...
It is.
...and that people here would know units of power. I need to stop making assumptions. It seems most of this forum isn't really tuned to these sort of questions by looking at the popular topics discussed.
Patience. I know what a watt is and I know the conversion I'm asking you to do. I'm trying to lead you to the answer, not hand it to you.

So: what is a Watt? By that, I mean, what units are combined to form it?
 
russ_watters said:
What is a watt?

It is.

Patience. I know what a watt is and I know the conversion I'm asking you to do. I'm trying to lead you to the answer, not hand it to you.

So: what is a Watt? By that, I mean, what units are combined to form it?
Okay wise guy, you want to get smart with me? Look I am just searching for a quick answer. I am not going down an absurd route of columbs, amperes, volts, watts, kilopascales, and Newton meters. Time is money and I have none to waist good day.
 
Chincha40 said:
Okay wise guy, you want to get smart with me? Look I am just searching for a quick answer.
Sorry, that isn't how this forum works. It's better for you (and probably us) if you learn how to find the answer than for us to just hand it to you.
I am not going down an absurd route of columbs, amperes, volts, watts, kilopascales, and Newton meters. Time is money and I have none to waist good day.
It's too bad: thisn't a hard problem and you could have learned how to do it by now if you hadn't wasted your (and our) time complaining about it and instead just followed me through it.
 
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