Hydraulic ram force calculation help?

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SUMMARY

To calculate the force of a hydraulic ram in Newtons, use the formula: Force (F) = Pressure (P) × Area (A). For a piston diameter of 20mm and an oil pressure of 52 bars, first convert the diameter to radius in meters (0.01m) and calculate the area using A = π × r². The area is approximately 3.14 × (0.01)² = 3.14 × 10⁻⁴ m². Therefore, the force is F = 52 × 10⁵ Pa × 3.14 × 10⁻⁴ m², resulting in a force of approximately 163.68 Newtons. The rod diameter of 4mm is not directly relevant to this calculation.

PREREQUISITES
  • Understanding of basic hydraulic principles
  • Knowledge of unit conversions (bars to Pascals)
  • Familiarity with geometric calculations for area
  • Basic algebra for manipulating formulas
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  • Study geometric formulas for calculating areas of circles
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rockabillyjim
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Hi, I was wondering how to calculate the force of a hydraulic ram in Newtons if the piston diametre is 20mm and the oil pressure is 52 bars. I would like it if someone could explain the formula as i can only find it with psi and imperial units on google. Also I have the shaft diametre of 4mm, I don't know if this is relevant

Thanks
Jim
 
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Formulas are generally given so that they work with consistent units. Are Newtons, mm, and bars consistent units?
 
I don't know. I probably sound a bit thick but I'm doing some homework for college and its beyond me.
 
Well, show us the formula you found online. We can start with that.
 
Ok here is the question. Calculate the force of the hydraulic ram when the oil pressure is 52 bars, the piston diameter is 20mm and the rod diameter is 4mm. I understand that I multiply the pressure by the area of the piston but I'm not sure weather I need to convert anything.
Thanks
 

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