Hydrogen Fluoride gas mixture quantities

AI Thread Summary
The discussion focuses on calculating the amount of hydrogen fluoride (HF) produced from a mixture of 17 tons of hydrogen and 8 tons of fluorine, relevant for a college assignment on European Seveso directives. The calculations indicate that fluorine is the limiting factor, resulting in the formation of approximately 8.4 tons of HF. This quantity, when combined with the initial amounts of hydrogen and fluorine, raises concerns about exceeding the upper threshold of 20 tons for Seveso site classification. The calculations confirm that the combination of these gases meets the criteria for a lower-tier Seveso site, but the potential HF production is critical for compliance. Understanding these quantities is essential for developing an effective emergency plan.
Rudi Rose
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Hi,

I am not a chemist but maybe there is somebody who can help me.
I need a put together an emergency plan as part of a college law assignment on European Seveso directives.
My case study has 17t of Hydrogen and 8t of Fluorine.
Both of which combine satisfy the requirement for a lower tier Seveso site.
8 (Quantity)/10 (treshold limit of fluorine) + 17/5 (treshold limit of hydrogen)...greater than 1 @4.2 makes it a lower tier site.
However if combined they create hydrogen fluoride which may push them over the upper threshold of 20t.
So my question how much hyrdrogen fluorine would be created with 17t of hydrogen ane 8t of fluorine.

Thanks

R
 
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Fluorine would be the limiting factor, with 19u/atom it catches a maximum of 1/19 of its mass as hydrogen to form 20/19*8t = 8.4 tons of HF.
 
Thanks mfb
 
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