# Hydrostatic Fluid- Linearly Accelerating Slope

1. Mar 15, 2014

### AnnaJa

1. The problem statement, all variables and given/known data
An open rectangular tank contains water up to about half of its depth. This tank accelerates at a=2.20 m/s$^{2}$ up a slope α (alpha), which causes the free water surface to form an angle θ (theta) with the original horizontal plane.
What is the α angle of the slope?

2. Relevant equations

p=ρh(g$\stackrel{+}{-}$a)
tanθ=$\stackrel{a}{g}$

3. The attempt at a solution

θ=tan$^{-1}($$\stackrel{199}{1242}$)=9.1°

angle between water surface and slope = γ

γ= α+θ

tanγ=($\stackrel{a}{g}$)

tanγ=($\stackrel{2.2}{9.81}$)

γ=12.64°

α=γ-θ=12.64-9.1=3.54°

I am not sure if this is the right approach?

Any help would be greatly appreciated.
Thank you, Anna

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Last edited: Mar 16, 2014