Hydrostatic pressure (infinitesimally small column of water)

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SUMMARY

Hydrostatic pressure is determined by the formula p = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the fluid. The discussion clarifies that hydrostatic pressure at the bottom of a water column is independent of the column's cross-sectional area. For a tank measuring 1 inch thick by 1 foot wide and 5 feet tall, the pressure at the bottom remains consistent at 300 pounds per square foot, regardless of the tank's dimensions. This confirms that pressure is a function of depth and density, not area.

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Infinitybyzero
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This is a hypothetical question: since hydrostatic pressure is calculated as depth of water times its density, would a column of water less than a square foot in cross section still have a pressure at the bottom of depth*density of water?

For example, if I had a 1" thick by 1ft wide by 5' tall tank of water, would the horizontal pressure be 300 pounds per square foot? Or 1/12 of that?
 
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Pressure does not depend on the area upon which it applies. The force resulting from that pressure on said surface does. So, regardless of the size of your tank, the hydrostatic pressure is always going to be ##p = \rho g h##, where ##\rho## is density, ##g## is gravity, and ##h## is the depth.
 

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