Is There a Simpler Way to Express Hyperbolic Coordinates in Terms of x and y?

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The discussion revolves around expressing hyperbolic coordinates in simpler terms of x and y. The current formulas provided are x = √((√(u²+v²)+u)/2) and y = √((√(u²+v²)-u)/2). Participants are exploring whether there is a more simplified method for these expressions. One suggestion includes squaring each equation to potentially derive new insights. The conversation emphasizes the challenge of simplifying these hyperbolic coordinate expressions.
brunotolentin.4
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This system of coordinates:

zahyou_hyporg.gif


can be "translated" in terms of x and y, so:
x = \sqrt{\frac{\sqrt{u^2+v^2}+u}{2}}
y = \sqrt{\frac{\sqrt{u^2+v^2}-u}{2}}
Exist another form more simplified of write x and y in terms of u and v? I tried rewrite these expressions using the fórmulas of half angle but didn't worked...
 
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brunotolentin.4 said:
This system of coordinates:

zahyou_hyporg.gif


can be "translated" in terms of x and y, so:
x = \sqrt{\frac{\sqrt{u^2+v^2}+u}{2}}
y = \sqrt{\frac{\sqrt{u^2+v^2}-u}{2}}
Exist another form more simplified of write x and y in terms of u and v? I tried rewrite these expressions using the fórmulas of half angle but didn't worked...
What about squaring each equation?
After you do that, maybe an idea will come to you.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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